Example: Solve |x + 1| < |2x - 3| - 4
1. Solve each absolute value for its zeros:
a. 2x – 3 = 0
b. x + 1 = 0
x =
3/2
x = -1
2. Mark them on a number line:
________________|________________________|_____________________
-1
3/2
3. Work with each interval:
a. x <
-1
b. -1 < x < 3/2
c. x > 3/2
2x
– 3 is negative
2x – 3 is
negative
2x – 3 is positive
x + 1 is
negative x
+ 1 is
positive
x + 1 is positive
so
the sentences to solve are:
________________|________________________|_____________________
-1
3/2
-x - 1 < -2x + 3 –
4
x + 1 < -2x + 3 –
4
x + 1 < 2x - 3 – 4
x <
0
3x <
-2
-x < -8
x <
-2/3
x > 8
In this interval, x < -1,
In this interval, -1 < x < 3/2
In this interval, x > 3/2,
so the
solutions
so –1 < x < -2/3 are
the
so x > 8 are the solutions.
are x < -1.
solutions.
4. Putting all the solutions together yields x <
-2/3
or x > 8
(Keep in mind that it is possible for the solutions
to be empty set or all reals.)
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