Let u = 2x - 3
du = 2 dx
du = dx
2
Multiply by sec x + tan x to
put the expression into a form that can be integrated.
sec x + tan x
Now, let u = sec x + tan x
du = (sec x tan x + sec2x) dx
So
Let u = cos x
du = - sin x dx
so
Go to Differential
Equations and Mathematical Modeling
Go to Calculus
Lessons Page
Go to Calculus
Page