Squiggly Line Method for Solving Polynomial Inequalities

Solve the inequality: 
                                           

  1. Draw a number line.
  2. Mark the points where the inequality equals 0 or is undefined -- in numerical order.  Use a closed circle for values that may be used as solutions and an open circle for values that make the expression undefined.

    ________o______________o______________o|___________o_____
                  -3                          -2                          1                          3
  3. Choose a point in one of the intervals, preferably the right or left end, and plug a number from that interval into the original equation to see if the answer would be positive or negative. If the answer is positive start the squiggly line above the number line and if it is negative start it below.  

    I chose to plug in +4.  The answer would be positive, so I start my squiggly line above the number line in the area where x would be larger than 3, and draw it down to meet the number line at 3.  I should also have closed circles on 3, -2, and 1, and an open circle on -3.

                                                                                                           _/
    ________o_____________o______________o___________o_/______
                  -3                          -2                          1                         3
  4. The factor from which the zero came has a power that is either even or odd. If the power is even, the squiggly line should bounce off that zero. If the power is odd, the squiggly line should go through that zero.

                                                                                                           /
                      ____________                               _____________   /
    _______o/___________\o_________   ___o/____________  \|o/______
            __ / -3                    -2\                         / 1                          3
        /                                      \________ __/
      /
    /

  5. The interval for which this squiggly line is below the number line or on the number line (marked by a closed circle) is the answer to this particular problem.

    Answer:  x < -3, -2 < x < 1, x = 3



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