If
, then F'(x)
= f(x)
PROOF:

This is the average value of f(t), so
since as h
®
0,
x
+ h ® x , then c®
x
EXAMPLE:
, then
If f(x) is continuous on [a,b], then
where F'(x) = f(x)
PROOF:
Starting with Part I, we know an antiderivative exists.
Let
so F(x) = G(x) + C
F(b) - F(a) = [ G(b) + C ] - [
G(a) + C ]
= G(b) - G(a)
ALTERNATE PROOF:
F(b) - F(a) = [F(xn ) - F(xn-1 )] + [F(xn-1 ) - F(xn-2 )] + ... + [F(x2 ) - F(x1 )] + [F(x1 ) - F(x0 )]
=
by
the Mean Value Theorem
and F'(c) (xi - xi-1 ) = F(xi
)
- F(xi-1 )
Then
Since F'(ci ) = f(ci ) = f(x), and Dx = dx = xi - xi-1 , then
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Then: there exists a c in (a,b) such that

Geometrically, there is a rectangle whose area is precisely equal to the area of the region under the curve.
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EXAMPLE: Find the average value of y = sin x from x = 0 to x = p

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ODD FUNCTIONS:
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(a number -- a definite integral)