Derivatives of Inverses
Properties of Inverses:
- f(f -1(x)) = f -1(f(x)) = x
- A function and its inverse are symmetric to each other over the line
y = x
- If (a, b) is on f(x), then (b, a)
is on f -1(x)
- If f(x) passes the horizontal line test, then its inverse
is also a function
- A function has an inverse if it is 1-1
- If a function is strictly monotonic, then it is 1-1 and
has an inverse function
- To see if a function is strictly monotonic, check its derivative
- If f(x) is continuous, then f -1(x)
is continuous
- If f(x) is increasing, then f -1(x)
is increasing; also, if f(x) is decreasing, then f
-1(x) is decreasing
- If f(x) is differentiable at x = c and
f(c) is not equal to 0, then f -1(x)
is differentiable at
x = f(c)
Derivative of an Inverse Function:
Let f -1(x) = g(x) Then
f(g(x)) = x
f
'(g(x))(g'(x)) = 1 (Take the derivative of both
sides)
g'(x)
= 1
f'(g(x))
Example:
- Find g'(x) if f(x) = 2x2 - 1
and g(x) = f -1(x)
- g(x) = \/((x + 1)/2) (Interchange x
and y in y = 2x2 - 1 and solve for
y)
- f'(x) = 4x
- g'(x) = 1 = 1 = 1 = \/2
f'(g(x)) f'(\/((x
+ 1)/2)) 4(\/((x
+ 1)/2) 4\/(x + 1)
- Find g'(7)
- \/2 = \/2 = 1 = 1
4\/(7 + 1) 4\/8 4\/4 8
- Find g'(7) using only the points and the derivative formula
- g'(7) = 1
f'(g(7))
- f(x) = 2x2 - 1
If 7 is an x value for g(x),
then 7 is a y value for f(x)
- 7 = 2x2 - 1
8 = 2x2
4 = x2
2,-2 = x
- g'(7) = 1 = 1
f'(2) 8
Problems