Also, the integral of y = e u is y = e u du.
Let u = 2x - 3
du = 2 dx
du = dx
2
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Change 3x to a number using base e.
Remember, e ln a = a.
So e ln3 = 3 and e x ln3
= 3x since x ln 3 = ln 3 x
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Let u = x ln3
du = ln 3 dx
du = dx
ln 3
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