cos A = adjacent
sec A = hypotenuse
hypotenuse
adjacent
tan A = opposite
cot A = adjacent
adjacent
opposite
| Angle | 0o
= 0 |
30o
= p 6 |
45o
= p 4 |
60o
= p 3 |
90o
= p 2 |
| Sin |
\/0 = 0
2 |
\/1 = 1
2 2 |
\/2
2 |
\/3
2 |
\/4 = 1
2 |
| Cos |
\/4 = 1
2 |
\/3
2 |
\/2
2 |
\/1 = 1
2 2 |
\/0 = 0
2 |
30o - 60o triangle
Draw a 30o - 60o triangle.
Draw another one congruent to it adjoining it.
We now have an equilateral triangle in which one side is 2r
in length.
In the diagram, ML = 2r, MO = r, and LO
must be found. Let x be the length of LO.
Using the Pythagorean Theorem, r2 + x2 =
(2r)2.
r2 + x2 = 4r2
x2 = 4r2 - r2
x2 = 3r2
x = r \/3
Now, the values of the trigonometric functions for 30o and 60o can be found from the definitions.
45o - 45o triangle
Draw a 45o - 45o triangle.
Let r be the length of the two equal sides.
O is the right angle.
Let x be the length of the hypotenuse.
Using the Pythagorean Theorem, r2 + r2 =
x2.
2r2 = x2
r \/2 = x
Now, the values of the trigonometric functions for 45o
can be found from the definitions.
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