Laws of Logarithms
- logbMN = logbM + logbN
Proof:
Let M = bx and N = by
Then MN = (bx)(by)
MN = bx + y
Write as a logarithm:
logbMN = x + y
Since M = bx, then logbM
= x
Since N = by, then logbN = y
And logbMN = logbM + logbN
- logb(M/N) = logbM - logbN
Proof:
Let M = bx and N = by
Then M = bx
N by
M = bx
- y
N
Write as a logarithm:
logb(M/N) = x - y
Since M = bx, then logbM
= x
Since N = by, then logbN = y
And logb(M/N) = logbM - logbN
- logbMk = k logbM
Proof:
Let M = bx
Then Mk = (bx)k
Mk = bxk
or bkx
Write as a logarithm:
logbMk = kx
Since M = bx, then logbM
= x
And logbMk = k logbM
- logbM = logbN if and only if
M = N
- logxM = logyM if and only if
x = y
Problems